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Mean Median Mode Range Worksheets and Help

Welcome to the Math Salamanders Mean Median Mode Range Worksheets. Here you will find a wide range of free printable Worksheets, which will help your child learn how to find the mean, median, mode and range of a set of data points.

These worksheets are aimed at students in 5th and 6th grade.

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Mean Median Mode Range Worksheets

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What is the Mean?

The mean is the average of a set of numbers.

It is found by adding up the set of numbers and then dividing the total by the number of data points in the set.

How to find the mean

Step 1) Add up all the numbers in the set.

Step 2) Divide the total by the total number of data points in the set.

Example 1) Find the mean of 5, 7, 8 and 4

Step 1) Add up the numbers to give a total of 5+7+8+4=24

Step 2) Divide the total by the number of data points. 24 ÷ 4 = 6

Answer: the mean is 6.

Example 2) Find the mean of 8, 2, 5, 7 and 13

Step 1) Add up the numbers to give a total of 8+2+5+7+13=35

Step 2) Divide by the number of data points. 35 ÷ 5 = 7

Answer: the mean is 7.

What is the Median?

The median is the midpoint (or middle value) of a set of numbers.

It is found by ordering the set of numbers and then finding the middle value in the set.

How to find the median

Step 1) Order the numbers in the set from smallest to largest.

Step 2) Find the middle number.

- If there is an odd number of values in the set, then the median is the middle value.

- If there is an even number of values in the set, then the median is the average of the two middle values.

Example 1) Find the median of 5, 7, 8, 2 and 4

Step 1) Put the numbers in order: 2, 4, 5, 7, 8

Step 2) There is an odd number of values in the set so the median is the middle value which is 5.

Answer: the median is 5.

Example 2) Find the median of 23, 27, 16, 31

Step 1) Put the numbers in order: 16, 23, 27, 31

Step 2) There is an even number of values in the set, so the median is the average of the middle two values.

(23+27) ÷ 2 = 25

Answer: the mean is 25

Example 3) Find the median of 7, -4, 9, -7, -2, 5

Step 1) Order the numbers: -7, -4, -2, 5, 7, 9

To get the average, simply add the two values together and divide by 2:

(-2 + 5) ÷ 2 = 1.5

Answer: the mean is 1.5

What is the Mode?

The mode is the most common (or the data point that appears most often) in a set of data.

It can be found by putting the data into an ordered list and seeing which data point occurs most often.

How to find the mode

Step 1) Put the data into an ordered list.

Step 2) Check that you have got the same number of data points.

Step 3) The mode is the data point which is the most common.

Finding the Mode Examples

Example 1) Find the mode of 3, 6, 4, 3, 2, 4, 7, 8, 6, 3, 9

This gives us: 2, 3, 3, 3, 4, 4, 6, 6, 7, 8, 9

Step 2) Check the number of data points in both lists is the same.

Both lists have 11 data points.

Step 3) The mode is the number which occurs most often.

Answer: the mode is 3.

Example 2) Find the mode of 0.6, 0.3, 0.4, 0.2, 0.4, 0.7, 0.6, 0.1, 0.4, 0.9

This gives us: 0.1, 0.2, 0.3, 0.4, 0.4, 0.4, 0.6, 0.6, 0.7, 0.9

Both lists have 10 data points.

Answer: the mode is 0.4.

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What is the Range?

The range is the gap between the smallest and largest data point.

It is found by putting the data into an ordered list and find the difference between the largest and smallest amount.

How to find the range

Step 3) The range is the difference between the largest and smallest data point.

To find the range simply subtract the smallest number from the largest number.

Finding the Range Examples

Example 1) Find the range of 14, 21, 9, 32, 27, 15, 12, 30

This gives us: 9, 12, 14, 15, 21, 27, 30, 32

Both lists have 8 data points.

Step 3) The range is the difference or gap between the largest and smallest numbers.

Answer: the range is 32-9=23.

Example 2) Find the range of 6, 2, -7, 2, -5, 11, 3, -4, 0, 9

This gives us: -7, -5, -4, 0, 2, 2, 3, 6, 9, 11

Answer: the range is 11-(-7)=18.

These printable mean median mode range worksheets have been carefully graded to ensure a progression in the level of difficulty.

Sheets 1, 2 and 3 are designed for 5th graders involve ordering and calculating using positive integers and decimals.

Sheets 4, 5 and 6 are designed for 6th graders and involve ordering and calculating with positive and negative numbers and decimals.

The first sheet involve finding the mean, median, mode and range of some positive whole numbers.

The 2nd sheet involves the use of decimals to 1dp.

The 3rd sheet is similar to the 2nd sheet but has many more data points.

The 4th sheet involves decimals and negative numbers.

The 5th and 6th sheets are similar to the 4th sheets but with increased number of data points.

  • Mean Median Mode and Range Sheet 1
  • PDF version
  • Median Mean Mode and Range Sheet 2
  • Median Mean Mode and Range Sheet 3
  • Median Mean Mode and Range Sheet 4
  • Median Mean Mode and Range Sheet 5
  • Median Mean Mode and Range Sheet 6

Mean Median Mode Range Problems

These printable mean median mode range problem sheets will help your child to use and apply their skills to solve problems.

The first problem sheet is more suitable for 5th grade and the second sheet is aimed at 6th graders.

  • Median Mean Mode and Range Problems 1
  • Median Mean Mode and Range Problems 2

Mean Median Mode Range Walkthrough Video

This short video walkthrough shows the problems from our Median Mean Mode and Range Problems Sheet 2 being solved and has been produced by the West Explains Best math channel.

If you would like some support in solving the problems on these sheets, check out the video!

More Recommended Math Worksheets

Take a look at some more of our worksheets similar to these.

  • Mean Worksheets

The sheets in this section will help you to find the mean of a range of numbers, including negative numbers and decimals.

There are a range of sheets involving finding the mean, and also finding a missing data point when the mean is given.

  • Median Worksheets

The sheets in this section will help you to find the median of a range of numbers, including negative numbers and decimals.

On some of the easier sheets, only odd numbers of data points have been used.

On the harder sheets, both odd and even numbers of data points have been included.

  • Mode and Range Worksheets

The sheets in this section will help you to find the mode and range of a set of numbers, including negative numbers and decimals.

There are easier sheets involving fewer data points, and harder ones with more data points.

The sheets in this section will help you to solve problems involving bar graphs and picture graphs.

There are a range of sheet involving reading and interpreting graphs as well as drawing your own graphs.

  • Box Plot Worksheets

Here are our selection of box plot worksheets to help you practice creating and interpreting box plots.

Mean, Median, Mode and Range Online Quiz

Our quizzes have been created using Google Forms.

At the end of the quiz, you will get the chance to see your results by clicking 'See Score'.

This will take you to a new webpage where your results will be shown. You can print a copy of your results from this page, either as a pdf or as a paper copy.

For incorrect responses, we have added some helpful learning points to explain which answer was correct and why.

We do not collect any personal data from our quizzes, except in the 'First Name' and 'Group/Class' fields which are both optional and only used for teachers to identify students within their educational setting.

We also collect the results from the quizzes which we use to help us to develop our resources and give us insight into future resources to create.

For more information on the information we collect, please take a look at our Privacy Policy

We would be grateful for any feedback on our quizzes, please let us know using our Contact Us link, or use the Facebook Comments form at the bottom of the page.

This quick quiz tests your knowledge and skill at finding and using the mean, median, mode and range of a set of data.

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  • Mean, Median, Mode and Range

Central Tendency Worksheets: Mean, Median, Mode and Range

Mean, median, mode and range worksheets contain printable practice pages to determine the mean, median, mode, range, lower quartile and upper quartile for the given set of data. The pdf exercises are curated for students of grade 3 through grade 8. Interesting word problems are included in each section. Sample some of these worksheets for free!

Finding Average

Finding Average

Average or mean worksheets have plentiful exercises to find the average of numbers, numbers with practical units and decimals.

(49 Worksheets)

Finding Range

Finding Range

Identify the maximum and minimum values to find the range of the given data. Word problems are included for practice.

  • Download the set

Finding Median

Finding Median

In these worksheets, 3rd grade and 4th grade children identify the median (middle value) of the represented data. Two word problems included.

Finding Quartiles

Finding Quartiles

Determine the first (lower) quartile, second (median) quartile and the third (upper) quartile of the given data. One word problem included in each pdf worksheet for 5th grade and 6th grade students.

Mean, Median, Mode and Range: Level 1

Mean, Median, Mode and Range: Level 1

These printable central tendency worksheets contain a mixed review of mean, median, mode and range concepts. Around 8 data are used in level 1.

Mean, Median, Mode and Range: Level 2

Mean, Median, Mode and Range: Level 2

Find the mean, median, mode and range of each set of data. Each sheet has six problems with around 15 data.

Word Problems: Level 1

Word Problems: Level 1

This exclusive section has five word problems to find the mean, median, mode and range of the given data.

Word Problems: Level 2

Word Problems: Level 2

A variety of informative data are included as word problems in these central tendency worksheet pdfs requires 7th grade and 8th grade students to determine the values of mean, median, mode and range.

Related Worksheets

» Line Plot

» Mean Absolute Deviation

» Stem and Leaf Plot

» Box and Whisker Plot

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Mean, Median, Mode and Range

Finding the mean, median, mode and range.

The three distinct calculations associated with the Measure of Central Tendency are the Mean , Median , and Mode . Each measurement is an attempt to capture the essence of how a typical entry or number in the data set may look like. The idea is to compute a single value that can represent the entire elements of the set.

In this lesson, I have prepared eight (8) worked examples to illustrate how to perform the required computations.

Measures of Central Tendency

Let’s first go over the main ideas of each measure of the central tendency.

Description: 

“Average” value of the set of numbers

How to find…

Add all numbers to get a total, then divide by the number of entries (number count of values you added).

Advantages:

  • Takes into account every number in the data set. That means all numbers are included in calculating the mean.
  • Easy and quick way to represent the entire data values by a single or unique number due to its straightforward method of calculation.
  • Each set has a unique mean value.

Disadvantages:

Its value is easily affected by extreme values known as the outliers.

Description:

Middle value of the set of numbers

  • Organize the numbers in increasing order, the median is the middle or centermost number.
  • If there are two middle numbers, add them and divide by 2 to get the median.
  • Not affected by the outliers in the data set. An outlier is a data point that is radically “distant” or “away” from common trends of values in a given set. It does not represent a typical number in the set.
  • The concept of the median is intuitive and thus can easily be explained as the center value.
  • Each set has a unique median value.

Its value is perceived as it is. It cannot be utilized for further algebraic treatment.

Most common or frequent value or item of the set

Tally or count how many times a number appears in the list of data. The mode is the one that shows the most.

  • Just like the median, the mode is not affected by outliers.
  • Useful to find the most “popular” or common item. This includes data sets that do not involve numbers.

If the set contains no repeating values, the mode is irrelevant. In contrast, if there are many values that have the same count, then mode can be meaningless. I did not include the range in the tabs above because it is not really a measure of central tendency. However, the concept of range is usually discussed alongside Mean, Median, and Mode. So, what is it then?

Range (in statistics) is the difference between the maximum and minimum values of the set. What the range provides is a quick and rough estimate of the spread of data values within a set.

Consider the two scenarios below. Here we have two classes taking Algebra 1 and the ages of the students in each class.

  • Algebra Class A

The ages of the students in Algebra Class A are 13, 13, 14, 14, 14, 15, 15, 15, 15, 16, 16, 16. To get the range, we subtract the number with the lowest value from the number with the highest value. So we have, Range = highest - lowest = 16-13 = 3. The Range is 3.

  • Algebra Class B

In Algebra Class B, the ages of the students in the class are 11, 13, 13, 14, 14, 15, 15, 15, 15, 16, 16, 18. We subtract the lowest value from the highest value to get the range. Therefore, Range = highest - lowest = 18 - 11 = 7. The range is 7.

Observations :

  • Since the range of Class A is smaller than in Class B, can we claim that the age distribution in Class A is more clustered (closely related) than in Class B? In other words, are the ages listed in Class A more uniform than in Class B?

Not so fast! This is, in fact, the biggest limitation of using the range to describe the spread of data within a set. The reason is that it can drastically be affected by outliers (values that are not typical as compared to the rest of the elements in the set).

  • Notice that when we disregard the outliers in Class B (ages 11 and 18), the “new” range becomes…

Disregarding the outliers, 11 and 18, in our dataset of 11, 13, 13, 14, 14, 15, 15, 15, 15, 16, 16, 18; our new lowest value becomes 13 and the new highest value becomes 16. Using the formula, Range = highest - lowest, we have 16 - 13 = 3. The range now becomes 3.

…which is now equal to the range of Class A. So the “big take” from this example is to be very careful when interpreting the values of the range, especially when comparing two sets.

Examples of How to Find the Mean, Median, Mode, and Range

Example 1: Find the mean, median, mode, and range for the following list of values

5, 13, 9, 7, 1, 9, 2, 9, and 11

The mean is commonly known as the “average” which is calculated by getting the sum of all values in the list and then divided by the number of entries. The symbol used to represent the mean is [latex]\bar X[/latex], often read as “x-bar”.

  • To find the mean:

Mean = add all the numbers in the set/number of entries = (5+13+9+7+1+9+2+9+11)/9 = 66/9 = 7.333... Mean ≈ 7

I rounded off the final answer to the nearest whole number because all the numbers in the set are also whole numbers. To be more specific, I rounded off the mean to the nearest “ones” place or digit.

Rounding off is an approximation so I use the wavy equal symbol [latex]\left( \approx \right)[/latex] to suggest that it is an estimate and not an exact answer. However, be proactive by asking your teacher how many decimal places to round off your final answer.

  • To find the median:

I must organize the numbers from lowest to highest, and identify the “middle” value.

Our original data set is 5, 13, 9, 7, 1, 9, 2, 9, and 11. Putting these numbers in ascending order to find the median, we have 1, 2, 5, 7, 9, 9, 9, 11, 13. Our median or middle value is the fifth number which is 9.

  In addition, since the number count of entries is odd , it is guaranteed to have a middle value. A quick shortcut to determine which entry is the median is to add the number of entries (call it [latex]x[/latex]) by 1 then divide by 2. Use the output value here to count from either the left or right of the ordered list to pinpoint the exact location of the median.

(x+1)/2 = nth entry where x represents the number of entries (must be odd) while the nth entry represents the location of the median.

From our previous problem, the number of count of elements in the set is [latex]x = 9[/latex] so we have

(x+1)/2 = (9+1)/2 = 10/2 = 5

Therefore, the median is located by finding the 5 th entry when counted from either the left or right of the ordered list.

  • To find the mode:

The mode is the number in the list that appears the most, which in this case, the number 9. This number is repeated three times.

In the data set 5, 13, 9, 7, 1, 9, 2, 9, and 11, the number 9 shows up the most. Thus the Mode = 9.

  • To find the range:

We don’t need to organize the list into numerical order to find the lowest and highest values. You should be able to pick those required two values by quick inspection.

After putting the numbers in ascending order, we have 1, 2, 5, 7, 9, 9, 9, 11, 13; we can see that the lowest value is 1 while the highest value is 13.

Since the range is the difference between the highest and lowest value, thus, range = highest − lowest = 13 − 1 = 12.

Example 2: Find the mean, median, mode, and range for the following list of values

4, 3, 7, 8, 4, 5, 12, 4, 5, 3, 2, and 3

Another way to solve for the mean is to use the formula

Mean = (∑x)/n

where the numerator is read as “the summation of all [latex]x[/latex] values”, and the denominator [latex]n[/latex] is just the number count of values in a set.

Mean = (∑x)/n = (4+3+7+8+4+5+12+4+5+3+2+3)/12 = 60/12 = 5. Therefore Mean = 5.

If we list the values in numerical order, the median is found at the “centermost” location. But here we have no single value at the center of the list. To address this issue, we are going to solve for the median by finding the average or mean of the two middle values .

The new order of our original numbers after putting them from lowest to highest is 2, 3, 3, 3, 4, 4, 4, 5, 5, 7, 8, 12. For this example, we have two middle numbers which are 4 and 4. The median is the average of the two middle numbers.

It just happens that the two center values are the same, therefore the average of two equal numbers will equal the same number.

Median = average of two middle values/2 = (4+4)/2 = 8/2 = 4. The median is 4.

By quick inspection, we should observe that two numbers (3 and 4) appear most frequently on the list. Can we say that we have a tie because they both repeat three times on the list? That precisely is the case. We have a situation here where two modes exist! Some textbooks would call this set bimodal, which means having two modes.

The numbers that appear the most are 3 and 4. Therefore, the mode is 3 and 4.

Range is equal to maximum value minus minimum value which gives us: 12 − 2 = 10 .

Example 3: Find the mean, median, mode and range for the following list of values

99, 23, 71, 18, 14, 50, and 13

To determine the value of the mean, obtain the total of all the numbers and then divide by the number of numbers in the list. Since all given values are whole numbers, then it makes sense to have the final answer also expressed as a whole. Therefore, I will round it off to the nearest ones’ place.

Mean = (∑x)/n = (99+23+71+18+14+50+13)/7 = 288/7 = 41.1428... Mean ≈ 41.

To solve for the median, let’s arrange the list in increasing order and then pick the center value. Obviously, the median here equals 23.

After putting the original set of values in increasing order, we have 13, 14, 18, 23, 50, 71, 99. Our median is the fourth number in the set which is 23.

To solve for the mode, identify the most “popular” value or entry in the list. Is there an element that appears more often in the list?

Arranging the numbers on the list from lowest to highest value also helps us identify the mode. However, in this example, every value only appears once. Therefore, there is no mode or mode = none.

It is apparent that no value is repeated more often than the other. In fact, each unique number only shows up one time. So, this set has no mode .

The range is the easiest to find, Range = highest value minus lowest value. This gives us RANGE = 99 − 13 = 86 .

Example 4: Find the mean, median, mode, and range for the following list of values

-5, -9, -35, 0, 3, -17, -5, and 0

This is an interesting example because the elements in the set now contain zeroes, a positive, and negative numbers. However, the methods that are used to solve for the mean, median, mode, and range do not change.

  • So for the mean , I will solve it as usual by finding its “average”. Since we are dealing with negative numbers, it is a good practice to place them inside the parenthesis to caution us to be careful in combining them. Round off your answer to the nearest ones’ place.

mean median mode range problem solving

  • For the median , we need to be careful in rearranging the numbers in increasing order because of the negative numbers. Remember that zero is always greater than any negative numbers. More so, to compare which of the two negative numbers is greater than the other, we need to compare both using their absolute values. The negative number with the smaller absolute value is the larger number!

Arranging our original set of numbers from least to greatest, we have -35, -17, -9, -5, -5, 0, 0, 3. Our two middle numbers are both -5, therefore, we have to get their average to find the median. Median = -5.

It just happens that the two middle numbers are equal. Thus, their average will simply be the number itself.

  • For the mode , find the elements of the set that appears more often. It looks like we also have a tie! Both − 5 and 0 repeat themselves twice. The modes then are − 5 and 0 .
  • The range is computed as follows:

Range = high - low = 3-(-35) = 3+35 = 38. The range is 38.

Remember that two negative signs turn out to be positive . Make sure that you always remember this simple rule to prevent any unnecessary algebraic mistakes.

Example 5: Find the mean, median, mode, and range for the following list of values

9.25, 12.31, 35.12, 56.13, 10.01, and 22.15

This example contains a set wherein all numbers have two decimal places. The rule of thumb is to ensure that any results of our computations must also be rounded off to the same decimal places. Again, it wouldn’t hurt if you ask advice from your teacher on how many decimals to round off as this part of the solution may be open to different interpretations.

  • Finding the mean:

Mean = (∑x)/n = (9.25+12.31+35.12+56.13+10.01+22.15)/6 = 144.97/6 = 24.16166... = 24.16. Mean = 24.16.

As you can see, I rounded off the final value of the mean to two decimal places.

  • Finding the median:

Arrange the numbers in increasing order – that is, from least to greatest. By having an even number of entries in the set suggests that we will have two middle numbers. This is always the case! You should anticipate getting the average of the two middle values to obtain the answer for the median.

To find the median, we need to arrange our original numbers in ascending order. So we have, 9.25, 10.01, 12.31, 22.15, 35.12, 56.13. Our two middle numbers are 12.31 and 22.15. The median is the average of the two middle numbers.

Here is the computation of the median…

Median = add the two middle numbers/2 = (12.31+22.15)/2 = 34.46/2 = 17.23. Median = 17.23.

After dividing the sum of two middle numbers by 2 yields an answer with two decimal places. This is perfect! No need to do some rounding off.

  • Finding the mode:

Since each element in the set appears just once (no repeating values), we say that this set has no mode .

  • Finding the range:

The highest value is 56.13, while the lowest value is 9.25. The range is just the difference between them.

Range = 56.13 − 9.25 = 46.88

Example 6: Find the mean, median, mode, and range for the following list of values

0.254, 0.38, 1.1, 6.3, 0.254, 1.1, 0.1, and 0.1

By quick inspection, the values in this set contain numbers that have different decimal places. Hopefully, you start by wondering how many decimal places should we round off the final answer. Again, this is open to interpretations. Therefore, I suggest that you ask your teacher for further clarification.

NOTE: For this problem though, I decided to round it off based on the number with the largest decimal places. I see that entry 0.254   contains three digits after the decimal point which is the biggest among others. So accordingly, I will keep in mind to round off the final answer for the mean with three digits after the decimal point.

  • Determining the mean:

Mean = (∑x)/n = (0.254+0.38+1.1+6.3+0.254+1.1+0.1+0.1)/8 = 9.588/8 =1.1985 = 1.199. Therefore, the mean is 1.199.

  • Determining the median :

Similar to example 5, this set has an even count of entries. Expect to average the middle two values to solve for the median. Remember to round off your answer to the nearest three decimal places just like when we solved for the mean.

We will arrange our numbers in ascending order to find the median. From lowest to highest, we have 0.1, 0.1, 0.254, 0.254, 0.38, 1.1, 1.1, 6.3. The two middle values are 0.254 and 0.38.

Here is the calculation for the median…

Median = sum of two middle values/2 = (0.254+0.38)/2 = 0.634/2 = 0.317.

  • Determining the mode:

We have three modes (trimodal) in this set which are 0.1, 0.254, and 1.1. They all repeat twice on the list!

  • Determining the range:

The maximum value in the list is 6.3, while the minimum value is 0.1. Therefore the range is computed as follows…

Range = maximum value - minimum value = 6.3 - 0.1 = 6.2. Therefore, Range = 6.2.

Example 7:  Leroy wants to achieve an overall grade of B on his quizzes. Currently, he has the following scores from his previous eleven quizzes: 75, 83, 96, 86, 69, 74, 83, 86, 90, 60, and 80 . What should be his next score in order to get a quiz average of 80?

Let “[latex]x[/latex]” be the unknown test score that Leroy needs to get. In order to set up the correct average, we need to make an adjustment on the number of entries being added: that is, from 11 to 12.

The working equation that can solve for the missing value of “[latex]x[/latex]” is the following…

Add all quiz scores/Number of quizzes = Desired quiz average → (75+83+96+86+69+74+83+86+90+60+80+x)/12 = 80 → 12 = (80)12 → 796+x = 960 → 796-882+x = 960-882 → x=78.

Leroy needs to score 78% on his next quiz in order to get a quiz average of 80%.

Example 8:  Lisa is aware that she needs to take five major exams in the semester. Unfortunately, due to medical reasons, she is only able to take two exams with scores of 85 and 89 . To accommodate her, the professor gives her a make-up exam that would count as three test grades. What score does she need to get on this make-up exam to garner a 90% average in all exams?

Assign a variable to the unknown score. Let’s call it “[latex]y[/latex]”. The total number of exams is 5 because of her existing two exam scores which is added to the make-up exam that is counted as three. The desired equation to solve for the required score is…

add all exam scores/number of exams = desired exam average → (85+89+y+y+y)/5 = 90 → (174+3y)/5 = 90 → 5 = (90)5 → 174+3y = 450 → 174-174+3y = 450-174 → 3y=276 → 3y/3 = 276/3 → y=92

Lisa needs to score 92% on this single exam that’s counted as three test grades to achieve an overall exam of 90%.

PRACTICE PROBLEMS ON MEAN MEDIAN AND MODE

Problem 1 :

Find the (i) mean  (ii) median  (iii) mode for each of the following data sets :

a)  12, 17, 20, 24, 25, 30, 40

b)  8, 8, 8, 10, 11, 11, 12, 12, 16, 20, 20, 24

c)  7.9, 8.5, 9.1, 9.2, 9.9, 10.0, 11.1, 11.2, 11.2, 12.6, 12.9

d)  427, 423, 415, 405, 445, 433, 442, 415, 435, 448, 429, 427, 403, 430, 446, 440, 425, 424, 419, 428, 441

Problem 2 :

Consider the following two data sets :

Data set A : 5, 6, 6, 7, 7, 7, 8, 8, 9, 10, 12

Data set B : 5, 6, 6, 7, 7, 7, 8, 8, 9, 10, 20

a)  Find the mean for both Data set A and Data set B.

b)  Find the median of both Data set A and Data set B.

c)  Explain why the mean of Data set A is less than the mean of Data set B.

d)  Explain why the median of Data set A is the same as the median of Data set B

Problem 3 :

The table given shows the result when 3 coins were tossed simultaneously 40 times. The number of heads appearing was recorded.

mean median mode range problem solving

Calculate the :   a)  mean     b)  median     c)  mode

Problem 4 :

The following frequency table records the number of text messages sent in a day by 50 fifteen-years-olds

mean median mode range problem solving

a)  For this data, find the : (i) mean   (ii)  median   (iii)  mode

b)  construct a column graph for the data and show the position of the measures of centre (mean, median and mode) on the horizontal axis.

c)  Describe the distribution of the data.

d)  why is the mean smaller than the median for this data ?

e)  which measure of centre would be the most suitable for this data set ?

Problem 5 :

The frequency column graph alongside gives the value of donations for an overseas aid organisation, collected in a particular street.

a)  construct the frequency table from the graph.

b)  Determine the total number of donations.

c)  For the donations find the :  (i)  mean   (ii)  median   (iii)  mode

d) which of the measures of central tendency can be found easily from the graph only ?

mean median mode range problem solving

Problem 6 :

Hui breeds ducks. The number of ducklings surviving for each pair after one month is recorded in the table.

a)  Calculate the : (i)  mean   (ii)  median   (iii) mode

b)  Is the data skewed ?

c)  How does the skewness of the data affect the measures of the middle of the distribution ?

mean median mode range problem solving

Answers 

(1)

Mean

Median

Mode

(a)

24

24

No mode

(b)

13.33

11.5

8

(c)

10.32

10

11.2

(d)

428.57

428

415 and 427

Set A

Mean  =  7.73

Median  =  7

Set B

Mean  =  8.45

Median  =  7

(c)  the mean of A is less than the mean of B.

(d)   median is the same.

(3)  (a)   Mean  =  1.4     (b)   median  =  1  (c)     mode  =  1

(4)  

(a)   (i)   Mean  =  5.74  (ii)     median  =  7  (iii)   mode  =  8

mean median mode range problem solving

(c)     bimodal data.

The mean takes into account the full range of numbers of text messages and is affected by extreme values. Also, the value which is lower than the median is well below it.

(e)   The median

(5)  

mean median mode range problem solving

(b)   ∑f  =  30

(c)  (i)   Mean  =  $2.9  (ii)   median  =  $2  (iii)   mode  =  $2

mean median mode range problem solving

(6)  

(a)  (i)  Mean  =  4.25    (ii)   median  =  5   (iii)   mode  =  5

mean median mode range problem solving

c)   By observing the graph, the mean is less than the median and mode.

mean median mode range problem solving

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  • Worksheet on Mean Median and Mode

In worksheet on mean median and mode the questions are based on finding the mean median and mode.

1. Find the mean of the following data.

(b) 16, 18, 19, 21, 23, 23, 27, 29, 29, 35

2.  Find the mean of first ten whole numbers.

3.  Find the mean of first 5 prime numbers.

4. The mean of 8, 11, 6, 14, x and 13 is 66. Find the value of the observation x.

5. The mean of 6, 8, x + 2, 10, 2x - 1, and 2 is 9. Find the value of x and also the value of the observation in the data.

6. Find the mean of the following distribution.

(a) The age of 20 boys in a locality is given below.

(b) Marks obtained by 40 students in an exam are given below.

(d) The daily wages of 50 employees in an organization are given below:

Find the mean daily wages.

(a) 12, 8, 4, 8, 1, 8, 9, 11, 9, 10, 12, 8

(b) 15, 22, 17, 19, 22, 17, 29, 24, 17, 15

(c) 0, 3, 2, 1, 3, 5, 4, 3, 42, 1, 2, 0

(d) 1, 7, 2, 4, 5, 9, 8, 3

8. The runs scored in a cricket match by 11 players is as follows:

7, 16, 121, 51, 101, 81, 1, 16, 9, 11, 16

Find the mean, mode, median of this data.

9. The weights in kg of 10 students are given below:

39, 43, 36, 38, 46, 51, 33, 44, 44, 43

Find the mode of this data. Is there more than 1 mode? If yes, why?

10. The marks obtained by 40 students out of 50 in a class are given below in the table.

Find the mode of the above data.

11. The number of rupee notes of different denominations are given below in the table.

12. Find the median of the following data.

(a) 27, 39, 49, 20, 21, 28, 38

(b) 10, 19, 54, 80, 15, 16

(c) 47, 41, 52, 43, 56, 35, 49, 55, 42

(d) 12, 17, 3, 14, 5, 8, 7, 15

13.  The following observations are arranged in ascending order. The median of the data is 25 find the value of x.

17, x, 24, x + 7, 35, 36, 46

14.  The mean of the following distribution is 26. Find the value of p and also the value of the observation.

Also, find the mode and the given data.

Answers for the worksheet on mean median and mode are given below to check the exact answers of the above questions.

5. 9, 11, 17

6. (a) 11.8

(d) no mode

8. Mean = 39 1/11;

Median = 16

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Mean, Median, Mode and Range -- Sorted Sets (Sets of 5 from 10 to 99) (A)

Welcome to The Mean, Median, Mode and Range -- Sorted Sets (Sets of 5 from 10 to 99) (A) Math Worksheet from the Statistics Worksheets Page at Math-Drills.com. This math worksheet was created or last revised on 2013-02-16 and has been viewed 106 times this week and 1,228 times this month. It may be printed, downloaded or saved and used in your classroom, home school, or other educational environment to help someone learn math.

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Problem worksheets for finding the mean, median, mode and range given a set of numbers. These are basic problems suitable for 'by-hand' calculations. The data in earlier problems are pre-sorted.

Easy Sorted Mean Median Range

Mean, Median, Mode and Range Worksheet Easy Sorted

Sorted Mean Median Range - Single Digits

Mean, Median, Mode and Range Worksheet Sorted Single Digits

Easy Mean Median Range

Mean, Median, Mode and Range Worksheet Easy

Mean Median Range - Single Digits

Mean, Median, Mode and Range WorksheetSingle Digits

Mean Median Range 2

Mean, Median, Mode and Range Worksheet 2

Mean Median Range 3

Mean, Median, Mode and Range Worksheet 3

Getting Started with Mean, Median, Mode and Range Problems

The worksheets on this page require kids to calculate the mean, median, range and mode for small sets of numbers, all of which are easy enough to add up on paper without the aid of a calculator. These are great practice tools for introducing concepts like mean or median because the sets of numbers are small enough to focus on the techniques to compute these statistics without getting bogged down in the calculations themselves.

Computing the median requires summing all the values in the set, so working initially with a small group of numbers is advantageous for learning the technique. Similarly, finding the median and the mode requires looking at the numbers in order, so making this a bit more frustrating if the set of numbers is large. Because of these issues, starting with this set of worksheets will build confidence in student's ability to tackle mean, median, mode and range problems before moving on to larger sets of numbers in the following sections...

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Grade 7 - Statistics & Probability

Standard 7.SP.B.4 - Given the mean, median, mode or range, find the missing number of a sample.

Included Skills:

Use measures of center and measures of variability for numerical data from random samples to draw informal comparative inferences about two populations. For example, decide whether the words in a chapter of a seventh-grade science book are generally longer than the words in a chapter of a fourth-grade science book.

If you notice any problems, please let us know .

Mean, Median and Mode from Grouped Frequencies

Explained with Three Examples

The Race and the Naughty Puppy

This starts with some raw data ( not a grouped frequency yet ) ...

runners

Alex timed 21 people in the sprint race, to the nearest second:

59, 65, 61, 62, 53, 55, 60, 70, 64, 56, 58, 58, 62, 62, 68, 65, 56, 59, 68, 61, 67

To find the Mean Alex adds up all the numbers, then divides by how many numbers:

Mean = 59 + 65 + 61 + 62 + 53 + 55 + 60 + 70 + 64 + 56 + 58 + 58 + 62 + 62 + 68 + 65 + 56 + 59 + 68 + 61 + 67 21 Mean = 61.38095...

To find the Median Alex places the numbers in value order and finds the middle number.

In this case the median is the 11 th number:

53, 55, 56, 56, 58, 58, 59, 59, 60, 61, 61 , 62, 62, 62, 64, 65, 65, 67, 68, 68, 70

Median = 61 

To find the Mode , or modal value, Alex places the numbers in value order then counts how many of each number. The Mode is the number which appears most often (there can be more than one mode):

53, 55, 56, 56, 58, 58, 59, 59, 60, 61, 61, 62, 62, 62 , 64, 65, 65, 67, 68, 68, 70

62 appears three times, more often than the other values, so Mode = 62

Grouped Frequency Table

Alex then makes a Grouped Frequency Table :

Seconds Frequency
51 - 55 2
56 - 60 7
61 - 65 8
66 - 70 4

So 2 runners took between 51 and 55 seconds, 7 took between 56 and 60 seconds, etc

puppy rips

Suddenly all the original data gets lost (naughty pup!)

Only the Grouped Frequency Table survived ...

... can we help Alex calculate the Mean, Median and Mode from just that table?

The answer is ... no we can't. Not accurately anyway. But, we can make estimates .

Estimating the Mean from Grouped Data

So all we have left is:

The groups (51-55, 56-60, etc), also called class intervals , are of width 5

The midpoints are in the middle of each class: 53, 58, 63 and 68

We can estimate the Mean by using the midpoints .

So, how does this work?

Think about the 7 runners in the group 56 - 60 : all we know is that they ran somewhere between 56 and 60 seconds:

  • Maybe all seven of them did 56 seconds,
  • Maybe all seven of them did 60 seconds,
  • But it is more likely that there is a spread of numbers: some at 56, some at 57, etc

So we take an average and assume that all seven of them took 58 seconds.

Let's now make the table using midpoints:

Midpoint Frequency
53 2
58 7
63 8
68 4

Our thinking is: "2 people took 53 sec, 7 people took 58 sec, 8 people took 63 sec and 4 took 68 sec". In other words we imagine the data looks like this:

53, 53, 58, 58, 58, 58, 58, 58, 58, 63, 63, 63, 63, 63, 63, 63, 63, 68, 68, 68, 68

Then we add them all up and divide by 21. The quick way to do it is to multiply each midpoint by each frequency:

Midpoint
x
Frequency
f
Midpoint × Frequency
fx
53 2 106
58 7 406
63 8 504
68 4 272
Totals:

And then our estimate of the mean time to complete the race is:

Estimated Mean =   1288 21   = 61.333...

Very close to the exact answer we got earlier.

Estimating the Median from Grouped Data

Let's look at our data again:

The median is the middle value, which in our case is the 11 th one, which is in the 61 - 65 group:

We can say "the median group is 61 - 65"

But if we want an estimated Median value we need to look more closely at the 61 - 65 group.

We call it "61 - 65", but it really includes values from 60.5 up to (but not including) 65.5.

Why? Well, the values are in whole seconds, so a real time of 60.5 is measured as 61. Likewise 65.4 is measured as 65.

At 60.5 we already have 9 runners, and by the next boundary at 65.5 we have 17 runners. By drawing a straight line in between we can pick out where the median frequency of n/2 runners is:

And this handy formula does the calculation:

Estimated Median = L +   (n/2) − B G  × w

  • L is the lower class boundary of the group containing the median
  • n is the total number of values
  • B is the cumulative frequency of the groups before the median group
  • G is the frequency of the median group
  • w is the group width

For our example:

  • B = 2 + 7 = 9

Estimating the Mode from Grouped Data

Again, looking at our data:

We can easily find the modal group (the group with the highest frequency), which is 61 - 65

We can say "the modal group is 61 - 65"

But the actual Mode may not even be in that group! Or there may be more than one mode. Without the raw data we don't really know.

But, we can estimate the Mode using the following formula:

Estimated Mode = L +   f m − f m-1 (f m − f m-1 ) + (f m − f m+1 )  × w

  • L is the lower class boundary of the modal group
  • f m-1 is the frequency of the group before the modal group
  • f m is the frequency of the modal group
  • f m+1 is the frequency of the group after the modal group

In this example:

Our final result is:

  • Estimated Mean: 61.333...
  • Estimated Median: 61.4375
  • Estimated Mode: 61.5

(Compare that with the true Mean, Median and Mode of 61.38..., 61 and 62 that we got at the very start.)

And that is how it is done.

Now let us look at two more examples, and get some more practice along the way!

Baby Carrots Example

carrots

Example: You grew fifty baby carrots using special soil. You dig them up and measure their lengths (to the nearest mm) and group the results :

Length (mm) Frequency
150 - 154 5
155 - 159 2
160 - 164 6
165 - 169 8
170 - 174 9
175 - 179 11
180 - 184 6
185 - 189 3
Length (mm) Midpoint
x
Frequency
f

fx
150 - 154 152 5 760
155 - 159 157 2 314
160 - 164 162 6 972
165 - 169 167 8 1336
170 - 174 172 9 1548
175 - 179 177 11 1947
180 - 184 182 6 1092
185 - 189 187 3 561
  Totals:

Estimated Mean =   8530 50   = 170.6 mm

The Median is the mean of the 25 th and the 26 th length, so is in the 170 - 174 group:

  • L = 169.5 (the lower class boundary of the 170 - 174 group)
  • B = 5 + 2 + 6 + 8 = 21

The Modal group is the one with the highest frequency, which is 175 - 179 :

  • L = 174.5 (the lower class boundary of the 175 - 179 group)

Age Example

Age is a special case.

When we say "Sarah is 17" she stays "17" up until her eighteenth birthday. She might be 17 years and 364 days old and still be called "17".

This changes the midpoints and class boundaries.

tropical island

Example: The ages of the 112 people who live on a tropical island are grouped as follows:

Age Number
0 - 9 20
10 - 19 21
20 - 29 23
30 - 39 16
40 - 49 11
50 - 59 10
60 - 69 7
70 - 79 3
80 - 89 1

A child in the first group 0 - 9 could be almost 10 years old. So the midpoint for this group is 5 not 4.5

The midpoints are 5, 15, 25, 35, 45, 55, 65, 75 and 85

Similarly, in the calculations of Median and Mode, we will use the class boundaries 0, 10, 20 etc

Age Midpoint
x
Number
f

fx
0 - 9 5 20 100
10 - 19 15 21 315
20 - 29 25 23 575
30 - 39 35 16 560
40 - 49 45 11 495
50 - 59 55 10 550
60 - 69 65 7 455
70 - 79 75 3 225
80 - 89 85 1 85
  Totals:

Estimated Mean =   3360 112   = 30

The Median is the mean of the ages of the 56 th and the 57 th people, so is in the 20 - 29 group:

  • L = 20 (the lower class boundary of the class interval containing the median)
  • B = 20 + 21 = 41

The Modal group is the one with the highest frequency, which is 20 - 29:

  • L = 20 (the lower class boundary of the modal class)
  • For grouped data, we cannot find the exact Mean, Median and Mode, we can only give estimates.

Estimated Mean = Sum of (Midpoint × Frequency) Sum of Frequency

  • n is the total number of data
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Problem Solving Averages and Range

Problem Solving Averages and Range

Subject: Mathematics

Age range: 11-14

Resource type: Worksheet/Activity

Rosiehns

Last updated

29 January 2018

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Mean, Median, Mode, Range Calculator

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The word mean, which is a homonym for multiple other words in the English language, is similarly ambiguous even in the area of mathematics. Depending on the context, whether mathematical or statistical, what is meant by the "mean" changes. In its simplest mathematical definition regarding data sets, the mean used is the arithmetic mean, also referred to as mathematical expectation, or average. In this form, the mean refers to an intermediate value between a discrete set of numbers, namely, the sum of all values in the data set, divided by the total number of values. The equation for calculating the arithmetic mean is virtually identical to that for calculating the statistical concepts of population and sample mean, with slight variations in the variables used:

mean equation

The mean is often denoted as x̄ , pronounced "x bar," and even in other uses when the variable is not x , the bar notation is a common indicator of some form of the mean. In the specific case of the population mean, rather than using the variable x̄ , the Greek symbol mu, or μ , is used. Similarly, or rather confusingly, the sample mean in statistics is often indicated with a capital X̄ . Given the data set 10, 2, 38, 23, 38, 23, 21, applying the summation above yields:

10 + 2 + 38 + 23 + 38 + 23 + 21
7
155
7

As previously mentioned, this is one of the simplest definitions of the mean, and some others include the weighted arithmetic mean (which only differs in that certain values in the data set contribute more value than others), and geometric mean . Proper understanding of given situations and contexts can often provide a person with the tools necessary to determine what statistically relevant method to use. In general, mean, median, mode and range should ideally all be computed and analyzed for a given sample or data set since they elucidate different aspects of the given data, and if considered alone, can lead to misrepresentations of the data, as will be demonstrated in the following sections.

The statistical concept of the median is a value that divides a data sample, population, or probability distribution into two halves. Finding the median essentially involves finding the value in a data sample that has a physical location between the rest of the numbers. Note that when calculating the median of a finite list of numbers, the order of the data samples is important. Conventionally, the values are listed in ascending order, but there is no real reason that listing the values in descending order would provide different results. In the case where the total number of values in a data sample is odd, the median is simply the number in the middle of the list of all values. When the data sample contains an even number of values, the median is the mean of the two middle values. While this can be confusing, simply remember that even though the median sometimes involves the computation of a mean, when this case arises, it will involve only the two middle values, while a mean involves all the values in the data sample. In the odd cases where there are only two data samples or there is an even number of samples where all the values are the same, the mean and median will be the same. Given the same data set as before, the median would be acquired in the following manner:

2,10,21, 23 ,23,38,38

After listing the data in ascending order, and determining that there are an odd number of values, it is clear that 23 is the median given this case. If there were another value added to the data set:

2,10,21, 23 , 23 ,38,38,1027892

Since there are an even number of values, the median will be the average of the two middle numbers, in this case, 23 and 23, the mean of which is 23. Note that in this particular data set, the addition of an outlier (a value well outside the expected range of values), the value 1,027,892, has no real effect on the data set. If, however, the mean is computed for this data set, the result is 128,505.875. This value is clearly not a good representation of the seven other values in the data set that are far smaller and closer in value than the average and the outlier. This is the main advantage of using the median in describing statistical data when compared to the mean. While both, as well as other statistical values, should be calculated when describing data, if only one can be used, the median can provide a better estimate of a typical value in a given data set when there are extremely large variations between values.

In statistics, the mode is the value in a data set that has the highest number of recurrences. It is possible for a data set to be multimodal, meaning that it has more than one mode. For example:

2,10,21,23,23,38,38

Both 23 and 38 appear twice each, making them both a mode for the data set above.

Similar to mean and median, the mode is used as a way to express information about random variables and populations. Unlike mean and median, however, the mode is a concept that can be applied to non-numerical values such as the brand of tortilla chips most commonly purchased from a grocery store. For example, when comparing the brands Tostitos, Mission, and XOCHiTL, if it is found that in the sale of tortilla chips, XOCHiTL is the mode and sells in a 3:2:1 ratio compared to Tostitos and Mission brand tortilla chips respectively, the ratio could be used to determine how many bags of each brand to stock. In the case where 24 bags of tortilla chips sell during a given period, the store would stock 12 bags of XOCHiTL chips, 8 of Tostitos, and 4 of Mission if using the mode. If, however, the store simply used an average and sold 8 bags of each, it could potentially lose 4 sales if a customer desired only XOCHiTL chips and not any other brand. As is evident from this example, it is important to take all manners of statistical values into account when attempting to draw conclusions about any data sample.

The range of a data set in statistics is the difference between the largest and the smallest values. While range does have different meanings within different areas of statistics and mathematics, this is its most basic definition, and is what is used by the provided calculator. Using the same example:

2,10,21,23,23,38,38 38 - 2 = 36

The range in this example is 36. Similar to the mean, range can be significantly affected by extremely large or small values. Using the same example as previously:

The range, in this case, would be 1,027,890 compared to 36 in the previous case. As such, it is important to extensively analyze data sets to ensure that outliers are accounted for.

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